# How do you solve sqrtv = 2?

Aug 5, 2015

$v = 4$

#### Explanation:

Take a look at what you have here

$\sqrt{v} = 2$

You take the square root from an unknown number $v$ and get an integer as the result. This automatically means that the number under the square root is a perfect square.

You can solve for $v$ by squaring both sides of the equation.

${\left(\sqrt{v}\right)}^{2} = {2}^{2}$

$v = \textcolor{g r e e n}{4}$

This is the only solution to your equation, $x = 4$, which is indeed a perfect square.