# How do you solve sqrtx+12=x?

Take $12$ to the right and then square both sides to get:
$x = {\left(x - 12\right)}^{2}$
$x = {x}^{2} - 24 x + 144$
${x}^{2} - 25 x + 144 = 0$
Solve for $x$ and then check the results (you´ll get 2 of which only one acceptable) by substituting back into your original equation.