How do you solve #sqrt(x^3) = 8#?
Square both sides:
I'm not sure a lot more explanation is needed: we do what we always do in algebra. That is, seek to make one pronumeral, in this case
(This is because, if the equals sign is to remain true, we must do the same thing to both sides at each step.)
You can also use the rule
x = 4
Pretty much, just a more in-depth proof of the earlier solution. Hopefully this helps!