How do you solve systems of linear equations by graphing #4x+y=13# and #2x-y=5#? {x+y=20 { x=3y 2x+4y=6 5x+10y=15?
1 Answer
May 30, 2017
See below:
Explanation:
I think I'm seeing 3 different systems of equations:
System 1: 4x+y=13; 2x-y=5
graph{(4x+y-13)(2x-y-5)=0}
System 2: x+y=20; x=3y
graph{(x+y-20)(x-3y)=0[10,20,0,10]}
System 3: 2x+4y=6; 5x+10y=15
graph{(2x+4y-6)(5x+10y-15)=0}
In this case, the two graphs are identical (they both reduce to