How do you solve systems of linear equations by graphing #4x+y=13# and #2x-y=5#? {x+y=20 { x=3y 2x+4y=6 5x+10y=15?

1 Answer

Answer:

See below:

Explanation:

I think I'm seeing 3 different systems of equations:

#System 1: 4x+y=13; 2x-y=5#
#System 2: x+y=20; x=3y#
#System 3: 2x+4y=6; 5x+10y=15#

System 1: 4x+y=13; 2x-y=5

graph{(4x+y-13)(2x-y-5)=0}

#(x,y)=(3,1)#

System 2: x+y=20; x=3y

graph{(x+y-20)(x-3y)=0[10,20,0,10]}

#(x,y)=(15,5)#

System 3: 2x+4y=6; 5x+10y=15

graph{(2x+4y-6)(5x+10y-15)=0}

In this case, the two graphs are identical (they both reduce to #y=-1/2x+3/2#) and so the solution set is all points along the line.