# How do you solve  t-3(t+4/3) = 2t+3?

$t = \frac{4}{7}$
 t-3t-4=2t+3
$t - 5 t = - 7$ (move all the $t$ to the left side and all the constants to the right side)
$- 4 t = - 7$ (the negative signs cancel out themselves)
$t = \frac{4}{7}$