# How do you solve the equation shown below algebraically: 6(x+1)-3(x-2)=x+4?

Oct 26, 2016

$x = - 4$

#### Explanation:

$6 \left(x + 1\right) - 3 \left(x - 2\right) = x + 4$

Open the brackets, multiplying the terms within with the number outside and keeping in mind that two negatives make a positive. Then simplify.

$6 x + 6 - 3 x + 6 = x + 4$

$3 x + 12 = x + 4$

Group all the x terms on the left and the integers on the right, changing values appropriately. Then simplify.

$3 x - x = 4 - 12$

$2 x = - 8$

Divide both sides by $2$.

$x = - 4$