# How do you solve the exponential inequality 5^(x-4)<=25^(x-6)?

$x \ge 8$
${5}^{x - 4} \le {5}^{2 \left(x - 6\right)}$ but $5 > 1$ then
$x - 4 \le 2 \left(x - 6\right) \to - 4 \le x - 12 \to x \ge 8$