How do you solve the inequality #10< 5-2d#?

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Answer 1 · 2016-02-08T21:48:51

#d<-5/2#

#10<5-2d#

Subtract 5 in both sides;

#5<-2d#

Now divide by -2. In inequalities if we divide or multiply
by negative numbers, we must change the comparison sign, i.e.

# a>b=>-a<-b#

So we have:

#-5/2>d#

Now we change again, for allowing the varaiable in the left side of the inequation:

#d<-5/2#