How do you solve the inequality #9x^2-6x+1<=0#?
Actually the left side can never be less than 0 for real numbers. It's lowest value is
You can see that from a diagram:
Since this is precalculus, I'm in doubt if derivation should be used in the solution, but using it you can show that a tangent at
Other than that we can write:
Since the left hand of the inequality is a square, we can conclude that it will never be negative, and it's lowest value is