# How do you solve the inequality #9x^2-6x+1<=0#?

##### 1 Answer

May 28, 2018

#### Explanation:

Actually the left side can never be less than 0 for real numbers. It's lowest value is

You can see that from a diagram:

Since this is precalculus, I'm in doubt if derivation should be used in the solution, but using it you can show that a tangent at

Other than that we can write:

Since the left hand of the inequality is a square, we can conclude that it will never be negative, and it's lowest value is