How do you solve the inequality $-x^2+14x-49>=0$ ?

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Answer 1 · 2016-12-30T04:53:50

Just x =7

Simplifying,

$(x-7)^2<=0$

As (x-7)^2>=0, the solution is (x-7)^2=0 to x = 7.9

The graph for this inequality reveals this point x = 7, on the x-axis

Geometrically,

this is the vertex ( 7, 0 ) of the parabola $y = (x-7)^2>=0$ .

Relating to this parabola, only the vertex x = 7 satisfies the

inequality.

graph{(x-7)^2<=0 [-10, 10, -5, 5]}

How do you solve the inequality -x^2+14x-49>=0-x^2+14x-49>=0?