How do you solve the inequality: #x^2 - 3x + 5 < 0#?

1 Answer
Aug 13, 2015

Answer:

This inequality has no solutions.

Explanation:

First step to solve such inequality is to calculate the determinant:

#Delta=b^2-4ac=(-3)^2-4*1*5=9-20=-11#

#Delta# is less than zero, and #a# is positive (1), so the whole graph of the function is above X axis.

graph{x^2-3x+5 [-9.96, 10.04, -4.92, 5.08]}

This means the inequality has no solutions.