How do you solve the system #10x^2-25y^2-100x=-160# and #y^2-2x+16=0#?
1 Answer
Feb 7, 2018
Solution is
Explanation:
We solve them as simultaneous equations. Here second equation gives us
or
or
or
or
i.e.
When
if
Hence, only solution is
Observe that while first equation representsa hyperbola, second equation is of a parabola. As parabola touches one arm of hyperbola at
graph{(10x^2-25y^2-100x+160)(y^2-2x+16)=0 [1.375, 11.375, -1.98, 3.02]}