# How do you solve the system #2x + 3y = 7# and #2x - 3y = 13# by graphing?

##### 1 Answer

#### Answer:

See a solution process below:

#### Explanation:

To solve for a system of equations by graphing. Solve for two points we each equation, plot the points, draw a line through the points, determine where the two lines intersect:

**Equation 1:**

**First Point:** For

**Second Point:** For

We can next plot the two points on the coordinate plane and draw a line through the two points:

graph{((x-2)^2+(y-1)^2-0.025)((x+1)^2+(y-3)^2-0.025)(2x+3y-7)=0 [-10, 10, -5, 5]}

**Equation 2:**

**First Point:** For

**Second Point:** For

We can next plot the two points on the coordinate plane and draw a line through the two points for the second equation:

graph{((x-2)^2+(y+3)^2-0.025)((x-5)^2+(y+1)^2-0.025)(2x+3y-7)(2x-3y-13)=0 [-10, 10, -5, 5]}

We can see the lines cross and

graph{((x-5)^2+(y+1)^2-0.05)(2x+3y-7)(2x-3y-13)=0 [-10, 10, -5, 5]}