# How do you solve the system 3x+2y=2, -2x+y=8?

Dec 26, 2016

$x = - 2$
$y = 4$

#### Explanation:

Since, by the second equation, it is

$y = 8 + 2 x$ $\textcolor{red}{\left(1\right)}$

you can put it in the first equation and get:

$3 x + 2 \left(8 + 2 x\right) = 2$

Then you multiply and get:

$3 x + 16 + 4 x = 2$

that's

$7 x = 2 - 16$

$7 x = - 14$

$x = - 2$

Then you put it in $\textcolor{red}{\left(1\right)}$ and get:

$y = 8 + 2 \left(- 2\right) = 8 - 4 = 4$