# How do you solve the system y=1/3x+2, y=-x-2 by graphing?

the answers are $x = - 3 , y = 1$
let,the given equations be $y = \frac{1}{3} x + 2 \to \left(1\right)$ and
$y = - x - 2 \to \left(2\right)$ equating the $R . H . S .$ part of both the equations we get $\frac{1}{3} x + 2 = - x - 2 \Rightarrow x + 6 = - 3 x - 6 \Rightarrow x + 3 x = - 6 - 6 \Rightarrow 4 x = - 12 \Rightarrow x = - 3$
substituting the value of $x$ in $e {q}^{n} \left(1\right)$ we get $y = \frac{1}{3} \left(- 3\right) + 2 = - 1 + 2 = 1$