How do you solve the system #y = 4x + 4# and #3x + 2y = 12# by graphing?
First, graph the Line 1 -> y1 = 4x + 4
Next, graph the Line 2 -> 3x + 2y = 12 (or
Evaluate the coordinate (x, y) of the intersection of the 2 Lines. That are the answers.
You may check the answer by algebraic method:
y1 = y2
4x + 4 = -3x/2 + 6 -> x