How do you solve the #triangle ABC# given #B=18^circ, C=142^circ, b=20#?

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Answer 1 · 2018-02-25T04:57:22

#color(blue)(hat A = 20^@, a = 22.136, c = 39.846#

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Given #hat B = 18, hat C = 142, b = 20#

#hat A = 180 - 18 - 142 = 20^@#

Applying Sine Law,

# a / sin A = b / sin B = c / sin C#

#a = (20 * sin A) / sin B = (20 * sin 20) / sin 18 ~~ 22.136#

#c =( 20 * sin 142 ) / sin 18 ~~ 39.846#