Question

How do you solve the triangle given A=33, b=2, a=3.5?

Answer 1

`angle C=128.8670923^o`
`angle B = 18.1329077^o`
`c= 5.00352111`

Explanation:

Using sine rule `(sin A)/a= (sin B)/b -> Sin B= 2/3.5 sin 33 =0.3112 -> angle B= 18.1329077^o`

`angle C= 180-(33+18.1329077)= 128.8670923^o`

Next, using `(sin C)/c= (sin A)/a, -> c= a (sin C)/ (sin A)=3.5 (sin 128.8670923)/(sin 33)=5.00352111`