Question

How do you solve the triangle given A=36, a=10, b=19?

Answer 1

There is no triangle possible with these measures.

Explanation:

We start with the law of sines.

`sin(36^@)/10=sin(B)/19`

`sin(B) = 19/10*sin(36^@)=1.9*sqrt((5-sqrt(5))/8)~~1.1168`

But we know that this is impossible because `sin(B)` must be less than or equal to 1, so we cannot construct a triangle with these measures.