An easy way to remember the trigonometric ratios in right angled

triangles:

Let opposite side be “t”

Let hypotenuse side be “s”

Let adjacent side be “a”

#Sin theta =(opposite)/ ( hypotenuse) = t/s = Sin(ts)#

#Cos theta = (adjacent ) /( hypotenuse ) = a/s = Cos(as)#

#Tan theta = (opposite)/(adjacent) = t/a = Tan(ta)#

#Cosec theta = (hypotenuse)/(adjacent) = s/t = Cosec(st)#

#Sec theta = (hypotenuse)/(adjacent) = s/a = Sec(sa)#

#Cot theta = (adjacent)/(opposite) = a/t = Cot(at)#

#180° -(70° 49'15.6''+90°)=19°10'44.4''= angleB#

#s/a = Sec 19°10'44.4''#

Multiply both sides by a

#s = Sec 19°10'44.4'' xx a#

#s= 1.058764789 xx 23#

#s = 24.352# = hypotenuse = side b#

Check:

#t/s = Sin 19°10'44.4'' #

Multiply both sides by s

#t= Sin 19°10'44.4'' xx s#

#t = 0.328520492 xx 24.352 #

#t = 8# = opposite side = b#