Question

How do you solve the triangle given m∠B = 73°, a = 7, b = 5?

Answer 1

Triangle can’t exist as `sin A > 1`

Explanation:

Given : `hatB = 73^@, a = 7, b = 5`

By the law of sines,

`a/ sin A = b / sin B = c / sin C`

`:. sin A = (a sin B) / b = (7 sin 73) / 5 = 1.3388`

Since, sine of an angle cannot have more than 1, such a triangle cannot exist.