How do you solve the triangle given m∠B = 73°, a = 7, b = 5?

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Feb 18, 2018

Answer:

Triangle can’t exist as #sin A > 1#

Explanation:

Given : #hatB = 73^@, a = 7, b = 5#

By the law of sines,

#a/ sin A = b / sin B = c / sin C#

#:. sin A = (a sin B) / b = (7 sin 73) / 5 = 1.3388#

Since, sine of an angle cannot have more than 1, such a triangle cannot exist.

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