# How do you solve (x + 13)(x - 19)>=0?

Aug 10, 2015

Answer: x in (-oo;-13> uu <19;+oo)

#### Explanation:

From tjhe inequality you can see, that your function has 2 zeros: ${x}_{1} = - 13$ and ${x}_{2} = 19$ and the function takes positive values when $x$ goes to $+ \infty$ and $- \infty$

graph{x^2-6x-247 [-40, 40, -20, 20]}

so you can write the solution: x in (-oo;-13> uu <19;+oo)

Aug 16, 2015

Solve $\left(x + 13\right) \left(x - 19\right) \ge 0$

Ans: (-infinity, -13] and [19, infinity)

#### Explanation:

The 2 x-intercepts (real roots) are x = -13 and x = 19.
Use the algebraic method to solve the inequality $f \left(x\right) \ge 0$. Between the 2 real roots f(x) < 0 as opposite to the side of a = 1.. Outside the interval (-13, 19), $f \left(x\right) \ge 0.$
Answer by half closed intervals: (-infinity, -13] and [19, infinity).
The critical points (-13) and (19) are included in the solution set.