How do you solve #x^2+12x=-32#?
Whenever we're dealing with quadratics, we want to set them equal to zero. We can do this by adding
Next, we need to think of 2 numbers that sum to
After some trial and error, we arrive at
Thus, we have:
The zeroes will be the opposite sign, and we get:
Hope this helps!
-4, and - 8
Solve this equation by the new Transforming Method (Socratic, Google Search), Case a = 1.
Find 2 real roots, that are both negative (ac > 0; ab > 0) knowing their sum (- b = - 12) and their product (c = 32).
They are: -4 and - 8.
Note . This method directly gives the 2 real roots. We don't have to factor by grouping and to solve the 2 binomials.