How do you solve $x^{2} - 14 x + 49 \geq 0$ $x^2-14x+49>=0$ using a sign chart?

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Answer 1 · 2017-01-01T09:55:14

The answer is $x in RR$

We need

$a^2-2ab+b^2=(a-b)^2$

$x^2-14x+49=(x-7)^2$

Let $f(x)=x^2-14x+49$

The domain of $f(x)$ is $D_f(x)=RR$

$AA x in RR, f(x)>=0$

We don't need a sign chart

graph{(x-7)^2 [-1.554, 16.226, -0.89, 8]}

How do you solve x^2-14x+49>=0x2−14x+49≥0x^2-14x+49>=0 using a sign chart?