How do you solve #x^2-14x+49>=0# using a sign chart?

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Answer 1 · 2017-01-01T09:55:14

The answer is #x in RR#

We need

#a^2-2ab+b^2=(a-b)^2#

#x^2-14x+49=(x-7)^2#

Let #f(x)=x^2-14x+49#

The domain of #f(x)# is #D_f(x)=RR#

#AA x in RR, f(x)>=0#

We don't need a sign chart

graph{(x-7)^2 [-1.554, 16.226, -0.89, 8]}