# How do you solve #(x-2)^2=-3#?

##### 1 Answer

May 1, 2016

#### Answer:

#### Explanation:

To solve this we want to take the square root of both sides, but the right hand side is negative. If

If

So given:

#(x-2)^2 = -3 = (sqrt(3)i)^2#

We must have:

#x-2 = +-sqrt(3)i#

Note the

Then adding

#x = 2+-sqrt(3)i#