# How do you solve (x+2)^2-(x-3)^2=35?

## d

##### 1 Answer
Sep 25, 2016

$x = 4$

#### Explanation:

$35 = {\left(x + 2\right)}^{2} - {\left(x - 3\right)}^{2}$

$\textcolor{w h i t e}{35} = \left(\textcolor{red}{\cancel{\textcolor{b l a c k}{{x}^{2}}}} + 4 x + 4\right) - \left(\textcolor{red}{\cancel{\textcolor{b l a c k}{{x}^{2}}}} - 6 x + 9\right)$

$\textcolor{w h i t e}{35} = 4 x + 4 + 6 x - 9$

$\textcolor{w h i t e}{35} = 10 x - 5$

Add $5$ to both ends and transpose to get:

$10 x = 40$

Divide both sides by $10$ to get:

$x = 4$