Question

How do you solve `(x+2)^2-(x-3)^2=35`?

d

Answer 1

`x=4`

Explanation:

`35 = (x+2)^2-(x-3)^2`

`color(white)(35) = (color(red)(cancel(color(black)(x^2)))+4x+4)-(color(red)(cancel(color(black)(x^2)))-6x+9)`

`color(white)(35) = 4x+4+6x-9`

`color(white)(35) = 10x-5`

Add `5` to both ends and transpose to get:

`10x = 40`

Divide both sides by `10` to get:

`x = 4`