How do you solve #(x+2)^2-(x-3)^2=35#?

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1 Answer
Sep 25, 2016

Answer:

#x=4#

Explanation:

#35 = (x+2)^2-(x-3)^2#

#color(white)(35) = (color(red)(cancel(color(black)(x^2)))+4x+4)-(color(red)(cancel(color(black)(x^2)))-6x+9)#

#color(white)(35) = 4x+4+6x-9#

#color(white)(35) = 10x-5#

Add #5# to both ends and transpose to get:

#10x = 40#

Divide both sides by #10# to get:

#x = 4#