# How do you solve #x^2+2x<0#?

##### 1 Answer

Mar 29, 2018

#### Answer:

#### Explanation:

Leading degree is 2 which tells us that

Now we can find roots to give us more details.

Let

This tells us that parabola passes x-axis at -2 and then again at 0.

So since parabola opens upward, it would below x-axis at anywhere between

graph{ x^2+2x [-3, 1, -2, 1]}Thus