# How do you solve #x^2+2x-3>=0#?

##### 1 Answer

#### Explanation:

The key to questions like this one is to solve it in the same way that you solve an equality (so one with an

- that if you multiply or divide by a negative number, you flip the greater than sign, and
- we'll be setting zones to see what is valid and what isn't.

So starting with the original:

we can factor this into:

and solve for x:

Ok, so we know that we have 3 zones:

And let's test

And we can test the right-most region with

So the answer in notation is

graph{x^2+2x-3>=0 [-10, 10, -1, 1]}