# How do you solve x^(2/3)+15=24?

Dec 9, 2016

$x = \pm 27$

#### Explanation:

Given:

${x}^{\frac{2}{3}} + 15 = 24$

Subtract $15$ from both sides to get:

${x}^{\frac{2}{3}} = 9$

Cube both sides to get:

${x}^{2} = 729$

Take the square root of both sides, allowing for both positive and negative square roots to get:

$x = \pm 27$

Assuming that we are dealing purely with Real numbers, both of these solutions are solutions of the original equation.