# How do you solve x^2-9x+8>0?

$x > 8 \mathmr{and} x > 1$
${x}^{2} - 9 x + 8 > 0 \to$
$\left(x - 8\right) \left(x - 1\right) > 0$
$x > 8 \mathmr{and} x > 1$