# How do you solve x^3+100<0?

##### 1 Answer
Jul 13, 2016

$x < - {100}^{\frac{1}{3}}$

#### Explanation:

First you move 100 over
${x}^{3} < - 100$
then you take the cube root to get rid of the cube. This is the same as
$x < - {100}^{\frac{1}{3}}$