Question

How do you solve `x^3<=4x^2`?

Answer 1

`x<=4`.

The Interval Form `: x in (-oo,4]`.

Explanation:

We rewrite the inequality as `4x^2-x^3>=0 rArr x^2(4-x)>=0`.

In this, since `x^2>=0, AA x in RR`, we must have, `4-x>=0`.

Therefore, `4>=x`, or,

`x<=4`, and, in the Interval Form, `x in (-oo,4]`.