How do you solve $x^3<=4x^2$ ?

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Answer 1 · 2016-07-27T18:21:30

$x<=4$ .

The Interval Form $: x in (-oo,4]$ .

We rewrite the inequality as $4x^2-x^3>=0 rArr x^2(4-x)>=0$ .

In this, since $x^2>=0, AA x in RR$ , we must have, $4-x>=0$ .

Therefore, $4>=x$ , or,

$x<=4$ , and, in the Interval Form, $x in (-oo,4]$ .

How do you solve x^3<=4x^2x^3<=4x^2?