How do you solve #-x/3-5=2x#?

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Answer 1 · 2018-03-03T04:26:16

#x=-5/7#

Times both sides by three:

#(-x/3 -5)*3=2x*3#

#-x-15=6x#

Then add #x# to both sides:

#-x-5+x=6x+x#

#-5=7x#

Finally, divide both sides by 7 to get #x# on its own:

#-5/7=(7x)/7#

#-5/7=x#

Therefore:

#x=-5/7 or ≈ 0.71#