# How do you solve x^3-9x= 0 by factoring?

$x = 0 \mathmr{and} x = - 3 \mathmr{and} x = 3$
${x}^{3} - 9 x = 0$
$\therefore x \left({x}^{2} - 9\right) = 0$
$\therefore x \left(x + 3\right) \left(x - 3\right) = 0$
$\therefore x = 0 \mathmr{and} x = - 3 \mathmr{and} x = 3$