# How do you solve ((x+3)(x-2))/(x+1)<0?

$x \setminus \in \left(- \setminus \infty , - 3\right) \setminus \cup \left(- 1 , 2\right)$

#### Explanation:

Given inequality

$\setminus \frac{\left(x + 3\right) \left(x - 2\right)}{x + 1} < 0$

Critical points of above inequality are

$x = 2 , - 1 , - 3$

Taking all the above critical points on the number line & dividing the regions in positive & negative intervals, we get the solution

$x \setminus \in \left(- \setminus \infty , - 3\right) \setminus \cup \left(- 1 , 2\right)$