Question

How do you solve `((x+3)(x-2))/(x+1)<0`?

Answer 1

`x\in(-\infty, -3)\cup(-1, 2)`

Explanation:

Given inequality

`\frac{(x+3)(x-2)}{x+1}<0`

Critical points of above inequality are

`x=2, -1, -3`

Taking all the above critical points on the number line & dividing the regions in positive & negative intervals, we get the solution

`x\in(-\infty, -3)\cup(-1, 2)`