# How do you solve #(x+3)/(x+4)<0#?

##### 1 Answer

#### Answer:

#### Explanation:

There are three intervals within which the sign of the quotient does not change:

#(-oo, -4)#

#(-4, -3)#

#(-3, oo)#

We do not need to consider the points

**Case #bb(x in (-oo, -4))#**

Both

So this interval is not part of the solution set.

**Case #bb(x in (-4, -3))#**

In this interval,

So this interval is part of the solution set.

**Case #bb(x in (-3, oo))#**

In this interval,

So this interval is not part of the solution set.

**Conclusion**

The solution set is the interval