How do you solve #x – 3sqrtx = 10 #?

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Answer 1 · 2016-07-19T19:59:46

#x - 10 = 3sqrt(x)#

#(x - 10)^2 = (3sqrt(x))^2#

#x^2 - 20x + 100 = 9x#

#x^2 - 29x + 100 = 0#

#(x - 25)(x - 4) = 0#

#x = 25 and 4#

Checking back in the initial equation, we find that only #x = 25# works. Hence, the solution set is #{25}#.

Hopefully this helps!