# How do you solve -x^4-16>0 using a sign chart?

Sep 11, 2017

There are no real solutions.

#### Explanation:

We have:

$- {x}^{4} - 16 > 0$

Giving:

${x}^{4} + 16 < 0$

And ${x}^{4} \ge 0 \forall x \in \mathbb{R} \implies {x}^{4} + 16 \ge 16 \forall x \in \mathbb{R}$

Hence there are no real solutions.