# How do you solve #(x+4)/x>0#?

##### 1 Answer

Jul 21, 2016

#### Answer:

#### Explanation:

If

That leaves two cases:

**Case #bb(x > 0)#**

Multiply both sides of the inequality by

#x+4 > 0#

Subtract

#x > -4#

Since

**Case #bb(x < 0)#**

Multiply both sides of the inequality by *reverse the inequality* (since the multiplier is negative) to get:

#x+4 < 0#

Subtract

#x < -4#

So

**Conclusion**

The solution set is the union of these two cases, namely:

#(-oo, -4) uu (0, oo)#