# How do you solve #(x+5)/(x-2)>0#?

##### 1 Answer

Dec 13, 2016

#### Explanation:

#(x+5)/(x-2) > 0#

This inequality will hold when both the numerator and denominator are positive or both negative.

The values of

So the intervals we need to consider are:

#(-oo, -5)# ,#(-5, 2)# and#(2, oo)#

When

When

When

So the solution space is:

#(-oo, -5) uu (2, oo)#

graph{(y(x-2)-(x+5))(x+0.0001y-2)(y-1+0.001x) = 0 [-10.63, 9.37, -4.44, 5.56]}