# How do you solve (x-8)(x+3)>0?

Dec 27, 2016

x>8 or x<-3
Interval notation $\left(- \infty , - 3\right) U \left(8 , \infty\right)$

#### Explanation:

This is a quadratic inequality. It would hold good if either both factors are >0 or both are <0

In the first case, when both are positive(>0), it would mean x>8 and x>-3. If x>8, then it would automatically be >-3. Hence if x>8, it would be a solution of the given inequality.

In the second case, when both are negative(<0), it would mean x<8 and x<-3. If x<-3, then it would automatically be <8. Hence if x<-3, it would be a solution of the given inequality.