# How do you solve (x + 9) ^ { 2} - 36= 0?

Apr 8, 2018

#### Answer:

$x = - 3 \mathmr{and} - 15$

#### Explanation:

${\left(x + 9\right)}^{2}$=36

$\left(x + 9\right) =$$\setminus \pm \sqrt{36}$

$x + 9 = 6$ or $x + 9 = - 6$

$x = - 3$ or $x = - 15$

Apr 8, 2018

#### Answer:

$x = - 15 \text{ or } x = - 3$

#### Explanation:

$\text{subtract 36 from both sides}$

${\left(x + 9\right)}^{2} \cancel{- 36} \cancel{+ 36} = 0 + 36$

$\Rightarrow {\left(x + 9\right)}^{2} = 36$

$\textcolor{b l u e}{\text{take the square root of both sides}}$

$\Rightarrow x + 9 = \pm \sqrt{36} \leftarrow \textcolor{b l u e}{\text{note plus or minus}}$

$\Rightarrow x = - 9 \pm 6$

$\Rightarrow x = - 9 - 6 = - 15$

$\text{or } x = - 9 + 6 = - 3$