# How do you solve #-x = sqrt(2x+15)# and find any extraneous solutions?

##### 1 Answer

May 7, 2017

#### Answer:

Solve for x then substitute the values in to verify that they are not extraneous solutions; x=5 is extraneous.

#### Explanation:

First, we solve for x:

If

therefore

If

Since the square root of a number cannot be negative,