# How do you solve #y=1/2x#, #y=-x+3# by graphing?

##### 1 Answer

See a solution process below:

#### Explanation:

First, solve for two points on the first equation, plot the two points and then draw a straight line through the two points:

**First Point:** For

**Second Point:** For

graph{(y - 0.5x)(x^2+y^2-0.035)((x-2)^2+(y-1)^2-0.035)=0 [-10, 10, -5, 5]}

Next, solve for two points on the second equation, plot the two points and then draw a straight line through the two points:

**First Point:** For

**Second Point:** For

graph{(y+x-3)(y - 0.5x)(x^2+(y-3)^2-0.035)((x-3)^2+y^2-0.035)=0 [-10, 10, -5, 5]}

We can see the lines intersect at

graph{(y+x-3)(y - 0.5x)((x-2)^2+(y-1)^2-0.035)=0 [-10, 10, -5, 5]}