How do you solve # y=2x^2-4x-48# by factoring?

1 Answer

Answer:

#y=2(x+4)(x-6)#
is the factored form of
#y=2x^2-4x-48#

Explanation:

#y=2x^2-4x-48#
Now,
Dividing the equation by 2
#1/2y=1/2(2x^2-4x-48)#
#1/2y=x^2-2x-24#
#x^2-2x-24=x^2+4x-6x-24#
#=(x^2+4x)-(6x+24)#

#1/2y=x(x+4)-6(x+4)#
#1/2y=(x+4)(x-6)#
#y=2(x+4)(x-6)#
is the factored form of
#y=2x^2-4x-48#