# How do you solve y>x+1 and y<2/3x + 3?

Jul 18, 2015

Solve the system:
(1) y > x + 1
(2) $y < \frac{2 x}{3} + 3$

#### Explanation:

First graph Line (1): y = x + 1 by its 2 intercepts.
Make x = 0 --> y = 1. Make y = 0 --> x = - 1.
The solution set of the inequality (1) is the area above the Line (1). Color or shade it.

Next, graph the Line (2): $y = \frac{2 x}{3} + 3$
Make x = 0 --> y = 3. Make y = 0 --> $x = - \frac{9}{2}$
The solution set of the inequality (2) is the area below this Line (2). Shade or color it.
The compound solution set of the system is the commonly shared area.