How do you solve #y=x-4#, #2y=-x+10# by graphing and classify the system?

1 Answer
Jun 30, 2016

Answer:

The (shared points) point of intersection is at #(x,y)->(6,2)#.

The system is of type: first order simultaneous equation system

Explanation:

For each equation:
Select at least 2 values for #x# and substitute into the equations to determine the corresponding values of y. Draw a line through each point extending it to the edge of the squares on the graph paper.

#color(blue)("Label all your points and put a title on your graph. Gives you extra")# #color(blue)("marks for good communication.")#

Equation 1
#y=x-4#

Equation 2
#2y=-x+10" "color(red)(vec("divide both sides by 2"))" " y=-x/2+5#
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
The system is a first order simultaneous equation system

Note:
#x->"first order"#
#x^2->"second order"#
#x^3->"third order"#

Tony B

Solution: The (shared points) point of intersection is at
#(x,y)->(6,2)#. The system is a first order simultaneous equation system