# How do you substitute to determine if the ordered pair (3, 2) is a solution of the system of equations 4x-y=10 and 3y=x+1?

Jul 10, 2017

$\left(3 , 2\right)$ is not a solution.

#### Explanation:

Given -

$4 x - y = 10$ -----------------(1)
$3 y = x + 1$-------------------(2)

We have to examine whether $\left(3 , 2\right)$ is a solution to the system of equations.

For this, you have to substitute $\left(3 , 2\right)$ in the two given equations.
If they are satisfied, $\left(3 , 2\right)$ is a solution, otherwise, it is not.

Take 1st equation

$4 \left(3\right) - 2 = 10$
$12 - 2 = 10$
$10 = 10$ -------------- Satisfied

Take the second equation

$3 \left(2\right) = 3 + 1$
$6 \ne 4$ ---------------- Not satisfied

$\left(3 , 2\right)$ is not a solution.