Question

How do you use `csctheta=5` to find `sec(90^circ-theta)`?

Answer 1

sec (90 - t) = 5

Explanation:

`csc t = 1/(sin t) = 5` --> `sin t = 1/5`
Unit circle and property of complement arcs -->
`cos (90 - t) = sin t`
There for
`sec (90 - t) = 1/(cos (90 - t)) = 1/(sin t) = 5`

Answer 2

`sec (90-theta) = 5`

Explanation:

`sec(90-theta) = csc theta`

`Given : csc theta = 5`

Using cofunctions,

`:. sec(90-theta) csc theta = 5`