How do you use Heron's formula to determine the area of a triangle with sides of that are 25, 16, and 22 units in length?

Area$= 173.636 \text{ }$square units

Explanation:

Compute half perimeter
$s = \frac{a + b + c}{2} = \frac{25 + 16 + 22}{2} = \frac{63}{2}$

Area$= \sqrt{s \left(s - a\right) \left(s - b\right) \left(s - c\right)}$

Area$= \sqrt{\frac{63}{2} \left(\frac{63}{2} - 25\right) \left(\frac{63}{2} - 16\right) \left(\frac{63}{2} - 22\right)}$

Area$= 173.636 \text{ }$square units

God bless....I hope the explanation is useful.